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P. 4

Single Correct Choice Type





            Each question in this section is a multiple choice question with four choices (A),
            (B), (C) and (D) out of which only one is correct.





           1. For any positive integer n, define f n : (0, ∞) → R as
                                         n
                                        X      −1             1
                                f n (x) =   tan                              for all x ∈ (0, ∞)
                                                   1 + (x + j)(x + j − 1)
                                        j=1
                                                                                   π π
                                                          −1
                Here, the inverse trigonometric function tan x assumes values in − ,     .
                                                                                   2 2
              Then, which of the following statement(s) is(are) TRUE?
                    5                                                10
                   P      2                                          P        0       2
               (A)    tan (f j (0)) = 55.                       (B)      1 + f (0) sec (f j (0)) = 10.
                                                                              j
                   j=1                                              j=1
                                                                      1
               (C) For any fixed positive integer n, lim tan (f n (x)) =  .
                                                  x→∞                n
                                                          2
               (D) For any fixed positive integer n, lim sec (f n (x)) = 1.
                                                  x→∞
                                                                                                    [JEE 2018]

           2. The equation of the plane passing through (1, 1, 1) and perpendicular to the planes 2x + y − 2z = 5
              and 3x − 6y − 2z = 7, is

               (A) 14x + 2y − 15z = 1.                          (B) 14x − 2y + 15z = 27.

               (C) 14x + 2y + 15z = 31.                         (D) −14x + 2y + 15z = 3.
                                                                                                    [JEE 2017]


           3. Let O be the origin and let PQR be an arbitrary triangle. The point S is such that
                            −→ −→       −→ −→       −→ −→       −→ −→       −→ −→       −→ −→
                            OP · OQ + OR · OS = OR · OP + OQ · OS = OQ · OR + OP · OS

              Then the triangle PQR has S as its
               (A) centroid.           (B) circumcentre.        (C) incentre.           (D) orthocenter.

                                                                                                    [JEE 2017]


           4. If y = y(x) satisfies the differential equation
                                                                            ! −1
                                                           r
                                  √    q      √                   q      √
                                8   x     9 +   x   dy =      4 +    9 +   x     dx,   x > 0
                          √
              and y(0) =    7, then y(256) =

               (A) 3.                  (B) 9.                   (C) 16.                 (D) 80.

                                                                                                    [JEE 2017]
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