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MODEL TEST PAPER 2 (SOLVED)
CLASS XI
COMPUTER SCIENCE (CODE 083)
Time Allowed: 3 hrs Maximum Marks: 70
General Instructions:
1. This question paper contains 37 questions.
2. All questions are compulsory. However, internal choices have been provided in some questions. Attempt
only one of the choices in such questions.
3. The paper is divided into 5 Sections—A, B, C, D and E.
4. Section A consists of 21 questions (1 to 21). Each question carries 1 Mark.
5. Section B consists of 7 questions (22 to 28). Each question carries 2 Marks.
6. Section C consists of 3 questions (29 to 31). Each question carries 3 Marks.
7. Section D consists of 4 questions (32 to 35). Each question carries 4 Marks.
8. Section E consists of 2 questions (36 to 37). Each question carries 5 Marks.
9. All programming questions are to be answered using Python language only.
10. In case of MCQ, text of the correct answer should also be written.
Section A (21 × 1 = 21 Marks)
1. State whether the following statement is True or False.? (1)
Intellectual Property (IP) infringement refers to any violation or breach of protected Intellectual
Property Rights.
Ans. True
2. Identify the output of the following code snippet. (1)
nums = [24, 26, 28, 30]
nums[2] = 32
print(nums)
(a) [24, 26, 28, 30] (b) [24, 26, 32, 30]
(c) [24, 32, 28, 30] (d) [24, 26, 32]
Ans. (b) [24, 26, 32, 30]
3. Cache memory is also called .......................... memory. (1)
Ans. CPU
4. What is tautology in Boolean statement or expression? (1)
(a) A statement that is always true (b) A statement that may be true or false
(c) A statement that is always false (d) A statement that is neither true nor false
Ans. (a) A statement that is always true
5. Which of the following will convert a string to a list of characters? (1)
(a) list() (b) str.split()
(c) str() (d) char()
Ans. (a) list()
6. Convert the following. (1)
(101011111) = ( ) 10
2
Ans. (101011111) = (351) 10
2
7. Which of the following is an invalid identifier in Python? (1)
(a) Sumval (b) Fibo_val
(c) Cust#ID (d) EmpName
Ans. (c) Cust#ID
M.8