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Matching-List & Matching-Matrix Type Jai Baba Ki7
7. Match the following two lists:
List-I List-II
" # 1/2
−1 −1 2 r
1 cos (tan y) + y sin (tan y) 1 5
(P) + y 4 takes (1)
−1
−1
y 2 cot (sin y) + tan (sin y) 2 3
value
√
(Q) If cos x + cos y + cos z = 0 = sin x + sin y + sin z, then (2) 2
x − y
possible value of cos is
2
π 1
(R) If cos − x cos 2x + sin x sin 2x sec x (3)
4 2
π
= cos x sin 2x sec x + cos + x cos 2x, then possible
4
value of sec x is
√ √
−1
2
(S) If cot sin −1 1 − x = sin tan (x 6), x 6= 0, then the (4) 1
possible value of x is
(P) (Q) (R) (S)
(A) (4) (3) (1) (2)
(B) (4) (3) (2) (1)
(C) (3) (4) (2) (1)
(D) (3) (4) (1) (2)
[JEE 2013]