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MODEL TEST PAPER – IV (Solved)

Time: 3 Hrs. M.M.: 70

1. a) What is the difference between type casting and automatic type conversion
in an expression? Give example of each. 2

Ans: Type Promotion: It is an implicit process of conversion of a data from one type to another. For
example
int n=65;

char ch=n; // automatic type conversion
cout<<ch;
Output will be A
Type Casting: It is an explicit process of conversion of a data from one type to another. For
example
int a=1, b=2;
float c=(float)a/b; // type casting

cout<<c;
Output will be 0.5
b) Observe the following C++ code and Write the names of the header files which
will be essentially required to run it : 1

void main()
{ int a, b;
randomize();
cin>>a;
b=random(a);
cout<<b;
}
Ans. iostream.h/iomanip.h and stdlib.h
c) Rewrite the following program after removing the syntactical errors (if any).

Underline each correction.( assuming all header files included) 2

#define area( a,b) a * b;
void main()
{ float x,y,z;
cin<<x<<y;
z=area[a,b];
cout<<” Area is :”<<z<<endline;
}
Ans: #define area( a,b) a * b
void main()
{ float x,y,z;
cin>>x>>y;
z=area(a,b);

XII / Comp. Sc. Page 1 of 17